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Synthetic parametric model: Difference between revisions

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we can then write down the state-space realisation <math> H(s,\varepsilon) =  \widehat{C}\Big(sI-\varepsilon \widehat{A}_\varepsilon + \widehat{A}_0\Big)^{-1}\widehat{B}+D</math> with
we can then write down the state-space realisation <math> H(s,\varepsilon) =  \widehat{C}\Big(sI-\varepsilon \widehat{A}_\varepsilon - \widehat{A}_0\Big)^{-1}\widehat{B}+D</math> with




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with <math> T = \left[\begin{array}{ccc} T_0 & & \\ & \ddots & \\ & & T_0 \end{array}\right] </math>,
with <math> T = \left[\begin{array}{ccc} T_0 & & \\ & \ddots & \\ & & T_0 \end{array}\right] </math>  
for <math>T_0 = \frac{1}{\sqrt{2}}\left[\begin{array}{cc} 1 & -j\\ 1 & j \end{array}\right]</math>.
and <math>T_0 = \frac{1}{\sqrt{2}}\left[\begin{array}{cc} 1 & -j\\ 1 & j \end{array}\right]</math>.


== Numerical values ==
== Numerical values ==

Revision as of 13:54, 28 November 2011

Introduction

On this page you will find a purely synthetic parametric model. The goal is to have a simple parametric model which one can use to experiment with different system orders, parameter values etc.

System description

The parameter ε scales the real part of the system poles, that is, pi=εai+jbi. For a system in pole-residue form


H(s)=i=1nrispi=i=1nris(εai+jbi),


we can then write down the state-space realisation H(s,ε)=C^(sIεA^εA^0)1B^+D with


εA^ε+A^0=ε[a1an]+[jb1jbn],

B^=[1,,1]T,C^=[r1,,rn],D=0.


Notice that the system matrices have complex entries.

For simplicity, assume that n is even, n=2k, and that all system poles are complex and ordered in complex conjugate pairs, i.e.

p1=εa1+jb1,p2=εa1jb1,,pn1=εak+jbk,pn=εakjbk,

which, for real systems, also implies that the residues form complex conjugate pairs r1,r¯1,,rk,r¯k.

Then a realization with matrices having real entries is given by


Aε=TA^εT*,A0=TA^0T*,B=TB^,C=C^T*,D=0,


with T=[T0T0] and T0=12[1j1j].

Numerical values

The numerical values for the different variables are

  • ri equally spaced in [103,1], with r1=1 and rk=103.
  • ai equally spaced in [101,103],
  • bi equally spaced in [10,103],
  • ε[1,20].



In MATLAB this is easily done as follows test