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Synthetic parametric model: Difference between revisions

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== Numerical values ==
== Numerical values ==


The numerical values for the different variables are
We construct a system of order <math>n = 100</math>. The numerical values for the different variables are


* <math> r_i = 1</math>,
* <math> r_i = 1</math>,
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* <math>b_i </math> equally spaced in <math>[10, 10^3]</math>,
* <math>b_i </math> equally spaced in <math>[10, 10^3]</math>,


* <math>\varepsilon \in [1/50,1]</math>.
* <math>\varepsilon</math><math> \in [1/50,1]</math>.




In MATLAB the system matrices are easily formed as follows


:<tt>
n = 100;


In MATLAB the system matrices are easily formed as follows
a = -linspace(1e1,1e3,n/2);
<tt>test</tt>
       
b = linspace(1e1,1e3,n/2);
</tt>

Revision as of 10:58, 29 November 2011

Introduction

On this page you will find a purely synthetic parametric model. The goal is to have a simple parametric model which one can use to experiment with different system orders, parameter values etc.

System description

The parameter ε scales the real part of the system poles, that is, pi=εai+jbi. For a system in pole-residue form


H(s,ε)=i=1nrispi=i=1nris(εai+jbi)


we can write down the state-space realisation H(s,ε)=C^(sIεA^εA^0)1B^+D with


εA^ε+A^0=ε[a1an]+[jb1jbn],
B^=[1,,1]T,C^=[r1,,rn],D=0.


Notice that the system matrices have complex entries.

For simplicity, assume that n is even, n=2k, and that all system poles are complex and ordered in complex conjugate pairs, i.e.

p1=εa1+jb1,p2=εa1jb1,,pn1=εak+jbk,pn=εakjbk,

which, for real systems, also implies that the residues form complex conjugate pairs r1,r¯1,,rk,r¯k.

Then a realization with matrices having real entries is given by


Aε=TA^εT*,A0=TA^0T*,B=TB^,C=C^T*,D=0,


with T=[T0T0] and T0=12[1j1j].

Numerical values

We construct a system of order n=100. The numerical values for the different variables are

  • ri=1,
  • ai equally spaced in [10,103],
  • bi equally spaced in [10,103],
  • ε[1/50,1].


In MATLAB the system matrices are easily formed as follows

n = 100;

a = -linspace(1e1,1e3,n/2);

b = linspace(1e1,1e3,n/2);